Answer:
Option C
Explanation:
$2SO_{2}+ O_{2}\rightleftharpoons 2SO_{3}$ K = 278 (given)
$SO_{3} \rightleftharpoons SO_{2} + 1/2O_{2}$ K' = $\left(\sqrt{\frac{1}{K}}\right)$
= $\left(\sqrt{\frac{1}{278}}\right)$ =$\sqrt{35.97\times10^{-4}}=6\times10^{-2}$